Q:

Brianna is graphing the function f(x) = x2 + 6x + 5. What x-intercepts should Brianna use to graph f(x)?–5 and –1–5 and 1–1 and 51 and 5

Accepted Solution

A:
Answer:First choice.Step-by-step explanation:The x-intercepts happen when y=0.Just like the y-intercepts happen when x=0.So anyways we are asked to find the x-intercepts.So set y=0 (set f(x)=0):0=x^2+6x+50=ax^2+bx+cSince a=1, all we have to do is find two numbers that multiply to be 5 and add up to be 6.Those numbers are 5 and 1 because 5(1)=5 and 5+1=6.So the factored form of x^2+6x+5 is (x+5)(x+1).The equation we have is:0=(x+5)(x+1).This means we have x+5=0 or x+1=0.We need to solve both equations.x+5=0Subtract 5 on both sides:x=-5x+1=0Subtract 1 on both sides:x=-1So the x-intercepts are at (-5,0) and (-1,0).ORSome people just say at -5 and -1.