MATH SOLVE

4 months ago

Q:
# Jim tree pays for shipping on the basis of weight. he knows weight is normally distributed so he can use the standard normal distribution. he decides to weigh 1,000 randomly trees in his shipment. next, he calculates the mean and standard deviation of their weights. he finds the mean is 30 lbs and the standard deviation is 10 lbs. now, jim uses the normal distribution table to calculate the number of trees in each segment of the distribution. standard deviation % from table no. of trees out of 1,000 0 to +1 (30 to 40 lbs) 34% +1 to +2 (40 to 50 lbs) 13.7% 137 +2 to +3 (50 to 60 lbs) 2.3% totals 50% 500

Accepted Solution

A:

Given that Jim
tree pays for shipping on the basis of weight. he knows weight is
normally distributed so he can use the standard normal distribution. he
decides to weigh 1,000 randomly trees in his shipment. next, he
calculates the mean and standard deviation of their weights. he finds
the mean is 30 lbs and the standard deviation is 10 lbs. now, jim uses
the normal distribution table to calculate the number of trees in each
segment of the distribution.

The required tabe is given as follows:

[tex]\begin{tabular}{|c|c|c|}standard deviation&\% from table&no. of trees out of 1,000\\[1ex]0 to +1 (30 to 40 lbs)&34\%&340\\+1 to +2 (40 to 50 lbs)&13.7\%&137\\+2 to +3 (50 to 60 lbs)&2.3\%&23\\Totals&50\%&500\end{tabular}[/tex]

The required tabe is given as follows:

[tex]\begin{tabular}{|c|c|c|}standard deviation&\% from table&no. of trees out of 1,000\\[1ex]0 to +1 (30 to 40 lbs)&34\%&340\\+1 to +2 (40 to 50 lbs)&13.7\%&137\\+2 to +3 (50 to 60 lbs)&2.3\%&23\\Totals&50\%&500\end{tabular}[/tex]