MATH SOLVE

4 months ago

Q:
# The price of Stock A at 9 a.m. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon, the price of Stock B was $16.53. It begins to decrease at the rate of $0.13 per hour. If the stocks continue to increase and decrease at the same rates, in how many hours will the prices of the stocks be the same?

Accepted Solution

A:

Answer:In approximately 3 hours time stock A will be the same price with Stock BStep-by-step explanation:Stock A increases at $ 0.05 per hourstock A at 9 a.m = $ 15.75stock A at 12 noon = $ 15 .75 + $ 0.05 * 3 = $ 15.75 + $ 0.15 = $ 15.90stock A in the next three hours again will be = $ 15.90 + $ 0.05 * 3 = $15.90 + $ 0.15 = $ 16.05Stock B at 12 noon = $ 16.53stock B decreases at $ 0.13 per hour so in the next three hours stock B will be = $ 16.53 - $ 0.13 * 3= $ 16.53 - $0.39 = $16.14